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8s^2-13s=-2/3
We move all terms to the left:
8s^2-13s-(-2/3)=0
We get rid of parentheses
8s^2-13s+2/3=0
We multiply all the terms by the denominator
8s^2*3-13s*3+2=0
Wy multiply elements
24s^2-39s+2=0
a = 24; b = -39; c = +2;
Δ = b2-4ac
Δ = -392-4·24·2
Δ = 1329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-39)-\sqrt{1329}}{2*24}=\frac{39-\sqrt{1329}}{48} $$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-39)+\sqrt{1329}}{2*24}=\frac{39+\sqrt{1329}}{48} $
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